Question

If alpha and beta are zeroes of quadratic x2 _ x _ 30 form a quadratic polynomial whose zeroes are 2 _ alpha and 2 _ beta

Answer 1

Answer:

$x^2-2x-120=0$

Step-by-step explanation:

$x^2-x-30=0\\\alpha+\beta=1\\\alpha\beta=-30\\ax^2+bx+c=a(x^2-(\alpha+\beta)x+\alpha\beta)\\Now the required QE is\\x^2-(2\alpha+2\beta)+4\alpha\beta=0\\x^2-2(\alpha+\beta)x+4\alpha\beta=0\\x^2-2x-120=0$

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