Question

if alpha and beta are zeroes of t^2-4t+3 find alpha^4 beta^3+alpha^3beta^4

Answer 1

t^2-4t+3=0
(t-3)(t-1)=0
t=3 & t=1
alpha(a)=3 & beta(B)=1
= (aB)^4/N + (aB)^4/a
=(3)^4/1 + (3)^4/3
=81/1 + 81/3
=81+27
=108