if alpha and beta are zeroes of the polynomial p(x)=x²-5x+6,then the value of alpha +beta-3 alphabeta
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Answered by
1
Hey
Here is your answer,
X^2 - 5x + 6 = 0
Sum of zeroes = -b/a
Alpha + beta = -(-5)/1 = 5
Product of zeroes = c/a
Alpha x beta = 6/1 = 6
Alpha + beta - 3 x alpha x beta = 5 - 3x6
= 5 - 18
= -13
Hope it helps you!
jacksom:
can you answer my another question
Answered by
0
x²-5x+6
here,
a = 1 , b = -5 and c = 6
sum of zeroes = -b/a
alpha + ß = 5
and,
product of zeroes = c/a
alpha × ß = 6.
therefore, alpha + beta - 3 × alphabeta = 5-3×6 = 5-18 = -13
here,
a = 1 , b = -5 and c = 6
sum of zeroes = -b/a
alpha + ß = 5
and,
product of zeroes = c/a
alpha × ß = 6.
therefore, alpha + beta - 3 × alphabeta = 5-3×6 = 5-18 = -13
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