Math, asked by jacksom, 1 year ago

if alpha and beta are zeroes of the polynomial p(x)=x²-5x+6,then the value of alpha +beta-3 alphabeta

Answers

Answered by sijasubbiah
1

Hey

Here is your answer,

X^2 - 5x + 6 = 0

Sum of zeroes = -b/a
Alpha + beta = -(-5)/1 = 5

Product of zeroes = c/a
Alpha x beta = 6/1 = 6

Alpha + beta - 3 x alpha x beta = 5 - 3x6
= 5 - 18
= -13

Hope it helps you!


jacksom: can you answer my another question
Answered by tingtongthegreat
0
x²-5x+6


here,

a = 1 , b = -5 and c = 6


sum of zeroes = -b/a

alpha + ß = 5

and,

product of zeroes = c/a

alpha × ß = 6.



therefore, alpha + beta - 3 × alphabeta = 5-3×6 = 5-18 = -13
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