if alpha and beta are zeroes of x^2 - x - 6, then find the value of alpha/beta+beta/alpha
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Step-by-step explanation:
x²-x-6
Roots are Alpha,beta
alpha/beta+beta/Alpha
alpha²+beta²/alpha×beta
we know
a²+b²=(a+b)²-2ab
so alpha²+beta²=(Alpha+beta)-2alpha×beta
=(1)-2×-6
=1+12
=13
alpha²+beta²=13
13/-6
-13/6 is the Answer
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