if alpha and beta are zeroes of x(square) - 4x + 3. then find a quadratic polynomial whose zeroes are 1/ alpha and 1/ beta
Answers
Answered by
34
Hey!
_____________
Let @ be alpha and ß be beta .
Now,
f (x) = x^2 - 4x + 3
a = 1
b = -4
c = 3
@ and ß are zeroes of f (x)
We know,
Sum of zeroes = -b/a
@ + ß = -b/a
= - (-4) / 1
= 4
Product of zeroes = c/a
@ß = c/a
= 3/1
= 3
We need to find a quadratic polynomial whose zeroes are 1/@ and 1/ß
Sum of zeroes = 1/@ + 1/ß
= @ + ß / @ß
= 4/3
Product of zeroes = 1/@ × 1/ß
= 1 / @ß
=1/3
We know,
Quadratic polynomial =
x^2 - ( @ + ß) x + (@ß)
= x^2 - (4/3) x + (1/3)
= x^2 - 4/3 x + 1/3
That's all!
_____________
Hope it helps...!!!
_____________
Let @ be alpha and ß be beta .
Now,
f (x) = x^2 - 4x + 3
a = 1
b = -4
c = 3
@ and ß are zeroes of f (x)
We know,
Sum of zeroes = -b/a
@ + ß = -b/a
= - (-4) / 1
= 4
Product of zeroes = c/a
@ß = c/a
= 3/1
= 3
We need to find a quadratic polynomial whose zeroes are 1/@ and 1/ß
Sum of zeroes = 1/@ + 1/ß
= @ + ß / @ß
= 4/3
Product of zeroes = 1/@ × 1/ß
= 1 / @ß
=1/3
We know,
Quadratic polynomial =
x^2 - ( @ + ß) x + (@ß)
= x^2 - (4/3) x + (1/3)
= x^2 - 4/3 x + 1/3
That's all!
_____________
Hope it helps...!!!
Anonymous:
nhi
Answered by
31
See the pic and ask if there is any doubt.
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