if alpha and beta are zeros of a quadratic polynomial x square - 5 then form a quadratic polynomial whose zeros are 1 + alpha and oneplus beta
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if alpha and bits are zeros of a quadratic polynomial X square - 5 then form a quadratic polynomial whose zeros are 1+alpha and 1+ bita
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Answered by
236
Answer:
quadratic polynomial whose zeros are 1 + α and 1 + β will be x² - 2x - 4
Step-by-step explanation:
Given ,
x² - 5 = 0
=> (x-√5)(x + √5) = 0
=> x = ±√5
hence
α = √5 and β = -√5
new roots
= 1 + α and 1 + β
= 1 + √5 and 1 - √5
hence the new equation will be
[x-(1+α)][x-(1+β)] = 0
=> [x-(1+√5)][x-(1-√5)] = 0
=> x² -(1+√5)x - (1-√5)x + (1+√5)(1-√5) = 0
=> x² - 2x + 1 - 5 = 0
=> x² - 2x - 4 = 0
which is the required quadratic equation
Answered by
41
Answer:
enjoy it's the right answer just apply ✓5 instead of 5
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