Question

if alpha and beta are zeros of p(x)=2x2-x-6,then find the value of alpha^-1+beta^-1

Answer 1

P(x)= 2x^2 -x -6
So by multiply the 1st and 3rd term it guves - 12 which suggests that one root is - ve.
P(x) = (2x^2 - 4x) (3x - 6)
= 2x (x - 2) +3 (x - 2)
= (2x + 3) (x - 2)
Alpha= 2 and Beta= - 3/2
Alpha^-1 + Beta^-1 = 1/2 - 2/3
= - 1/6

Answer 2

Answer:

Plz see the attachment

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