if alpha and beta are zeros of polynomial f(x)=px2+qx+r then find (i)alpha2+beta2 (ii)alpha/beta+beta/alpha (iii)alpha3+beta3
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Answer:
f(x)=px2 +qx +r;
sum of the roots= alpha+Beta =(-q/p);
product of the roots =alpha*beta= r/p;
Put these values in the expression
1/ (p.alpha+q) + 1/ (p.beta+q)
On solving you will get = q/(pr)
Thanks.
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