Question

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Answer 1

Answer:

first let's find the net resistance

in the upper branch two 5ohm resistor are in series so net resistance in upper branch will be 10 ohn

in the lower branch two 10ohm resistor are in series so net resistance in lower branch will be 20 ohn

net resistance will be

1/R=1/10+1/20

1/R=3/20

R=20/3

net current =R/v

I=20/3*6

I=20/18

I=10/9 Ampere

Explanation:

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Answer 2

$\frac{(5 + 5) \times (10 + 10)}{(5 + 5) + (10 + 10)} \\ = \frac{10 \times 20}{30} \\ = \frac{20}{3} \\ = 6.6667 \: ohm$

6.6667 Ohm

V = I×R

I = V/R = (6×3)/20 = 9/10 Ampere

Answer

0.9 A