If alpha and beta are zeros of polynomial x2-k (x+1) -a . Evalute (alpha + 1)(beta + 1)
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Answer:
Step-by-step explanation:
X² - kx - K -a = 0
A = 1 , b = -k, c = -k-a
Alpha + beta = -b/a
= -(-k) ÷1 = k
Alpha. Beta = c/a
= -k-a ÷ 1 = -k-a
(alpha +1)(beta +1)
Alpha (beta + 1) + 1 (beta + 1)
Alpha. Beta + alpha + beta + 1
-k-a + K + 1
= 1-a
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