Question

If alpha and beta are zeros of polynomial x2+p(x-1)+c such that (alpha+1)(beta+1)=0 then find the value of c

Answer 1

Answer:

c= -1

Step-by-step explanation:

(alpha+1)(beta+1)

alpha×beta+alpha+ beta+1

c-p+p+1=0

c+1=0

c= -1