Sum of n terms of an ap whose first term is p and common difference is q
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Answered by
0
Answer:
Sn= n/2(2a+(n-1)d)
a=p
d=q
n/2(2p+(n-1)q
np+qn-q
Step-by-step explanation:
Answered by
1
Answer:
An=n/2[2a+(n-1)d]
a=p, d=q
n/2[2p+(n-1)q]
np+qn-q
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