Question

Sum of three consecutive even interferes is 54. Find the least among them.

Answer 1

Answer:17

Step-by-step explanation:

Let the numbers be x x+1 and x+2

x+x+1+x+2=54

3x+3=54

3x=54-3

x=51/3

x=17

Therefore the numbers are 17 , 18 n 19

Smallest number = 17

Answer 2

Answer : 16

Step by step explanation:

Let the three consecutive even numbers be x, x + 2 and x + 4 respectively.

Hence, as per given condition,

x + (x + 2) + (x + 4) = 54

3x + 6 = 54

3x = 48

x = 16

x + 2 = 18

x + 4 = 20

Thus, the numbers are 16, 18 and 20.

Were asked to find the least number, thus the least number is 16

Answer : 16