If alpha and beta are zeros of quadratic polynomial x2-5x+6 then find the value of alpha^2 +beta^2
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Given: α & β are the zeroes of the quadratic Polynomial x² - 5x+6
Here, a=1,b= - 5 , c=6
Sum of zeroes = -b/a = -(-5/1) = 5
α + β = 5………………(1)
Product of zeroes = c/a = 6/1= 6
α β = 6………………..(2)
(α + β)² = α² +β² + 2α β
(5)² = α² +β² + 2(6) [from eq 1 & 2]
25 = α² +β² + 12
25 - 12 = α² +β²
13 = α² +β²
Hence, the value of α² +β² is 13.
HOPE THIS WILL HELP YOU...
Here, a=1,b= - 5 , c=6
Sum of zeroes = -b/a = -(-5/1) = 5
α + β = 5………………(1)
Product of zeroes = c/a = 6/1= 6
α β = 6………………..(2)
(α + β)² = α² +β² + 2α β
(5)² = α² +β² + 2(6) [from eq 1 & 2]
25 = α² +β² + 12
25 - 12 = α² +β²
13 = α² +β²
Hence, the value of α² +β² is 13.
HOPE THIS WILL HELP YOU...
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