if alpha and beta be two zeros of quadratic polynomial x2-7x+12. find a quadratic polynomial whose zeros are -alpha and -beta
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Step-by-step explanation:
In a quadratic equation, ax^2 + bx + c, sum S of roots is given by - b/a and product P of roots is c/a.
In this equation,
S = α + β = -(-7/1) = 7
P = αβ = 12/1 = 12
So, if we form an equation with roots -α and -β,
sum of roots = -α + (-β)
= - α - β = - (α + β)
= - 7
product of roots = (-α)(-β)
= (αβ)
= 12
Hence the required equation is,
⇒ x^2 - (-7)x + 12
⇒ x^2 + 7x + 12
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