Question

if alpha and beta is zero of x²-7x+12​

Answer 1

Answer:

3 and 4

Step-by-step explanation:

if alpha and beta are zeros , then:

$\alpha + \beta = 7 \\ \alpha \beta = 12$

if we want to calculate the value of these:

${x}^{2} - 7x + 12 \\ = {x}^{2} - 3x - 4x + 12 \\ = x(x - 3) - 4(x - 3) \\ = (x - 4)(x - 3)$

therefore alpha and beta are 3 and 4

Answer 2

$\begin{gathered} \alpha + \beta = - 7 \\ \alpha \beta = 12\end{gathered}$

$⇝\begin{gathered} = \frac{1}{ \alpha } + \frac{1}{ \beta } + 2 \alpha \beta \\ = \frac{ \alpha + \beta }{ \alpha \beta } + 2 \alpha \beta \\ = \frac{ - 7}{12} + 2(12) \\ = \frac{ - 7}{12} + 24 \\ = \frac{ - 7 +288 }{12} \\ = \frac{281}{12} \\ \end{gathered}$