if alpha and bita are roots x²+x-7=0 find value of alpha³+ bita³
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Step-by-step explanation:
ā and b are the roots of equation x²+x-7=0
a=-1
b= 7
now a³+b³= (a+b)(a²+b²-ab)
(-1+7)(-1³+7--1×7)
6(-1+7+7)
6(-1+14)
6(13)
78
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