Question

If alpha and bita are zeros of x2-(k-6)x+2(2k-1) if alpha + bita = 1/2alpha.bita

Answer 1

here is your answer. . .

Answer 2

Answer: k= -5

Step-by-step explanation:

alpha+bita=1/2alpha.bita      (given)

p(x)=x^2-(k-1)x+2(2k-1)

so, a=1 ; b=-(k-1) ; c=2(2k-1)

alpha+bita= -b/a

                 =-(-k-6/1)

                 =k-6                    (1)

1/2alpha.bita= 1/2 * c/a

                     =1/2 * 2(2k-1)/1

                      = 2k-1            (2)

from given and equation (1) and (2)

k-6=2k-1

-6+1=2k-k

-5=k

Therefore, k = -5