Question

Simplify 3√45 - √125 + √200 - √50
Brainliest answer for sure

Answer 1

$3 \sqrt{45} - \sqrt{ 125 } + \sqrt{200} - \sqrt{50} \\ \\ 3 \sqrt{9 \times 5} - \sqrt{25 \times 5} + \sqrt{2 \times 100} - \sqrt{2 \times 25} \\ \\ (3 \times 3) \sqrt{5} - 5 \sqrt{5} + 10 \sqrt{2} - 5 \sqrt{2} \\ \\ 9 \sqrt{5} - 5 \sqrt{5} + 10 \sqrt{2} - 5 \sqrt{2} \\ \\ 4 \sqrt{5} + 5 \sqrt{2}$




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Answer 2

Hello friends!!

Here is your answer :

$3 \sqrt{45} - \sqrt{125} + \sqrt{200} - \sqrt{50}$


$\sqrt{45} = \sqrt{3 \times 3 \times 5} = 3 \sqrt{5}$


$\sqrt{125} = \sqrt{5 \times 5 \times 5} = 5 \sqrt{5}$


$\sqrt{200} = \sqrt{2 \times 2 \times 2 \times 5 \times 5} = 2 \times 5 \sqrt{2} = 10 \sqrt{2}$


$\sqrt{50} = \sqrt{2 \times 5 \times 5} = 5 \sqrt{2}$



$= > 3(3 \sqrt{5} ) - (5 \sqrt{5} ) + (10 \sqrt{2} ) - 5 \sqrt{2}$


$= > 9 \sqrt{5} - 5 \sqrt{5} + 10 \sqrt{2} - 5 \sqrt{2}$


$= > 4 \sqrt{5 } + 5 \sqrt{2}$


Hope it helps you... ☺️☺️☺️☺️

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