Math, asked by jvsaravanan, 10 months ago

If alpha and one by Alpha are the zeros of the polynomial X square + 11 x minus A minus 2 find the value of k

Answers

Answered by Anonymous
2

\huge\boxed{\fcolorbox{green}{orange}{Answer}}

Compare 4x² - 2x + ( k - 4 ) with

ax² + bx + c ,

a = 4 ,

b = - 2 ,

c = k - 4 ,

Product of the zeroes = c/a

Alpha × 1/alpha = ( k - 4 ) / 4

1 = ( k - 4 ) / 4

4 = k - 4

4 + 4 = k

8 = k

Therefore ,

k = 8

Answered by Avni2348
2

Answer:

Compare 4x² - 2x + ( k - 4 ) with

ax² + bx + c ,

a = 4 ,

b = - 2 ,

c = k - 4 ,

Product of the zeroes = c/a

Alpha × 1/alpha = ( k - 4 ) / 4

1 = ( k - 4 ) / 4

4 = k - 4

4 + 4 = k

8 = k

Therefore ,

k = 8

Similar questions