If alpha and one by Alpha are the zeros of the polynomial X square + 11 x minus A minus 2 find the value of k
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Compare 4x² - 2x + ( k - 4 ) with
ax² + bx + c ,
a = 4 ,
b = - 2 ,
c = k - 4 ,
Product of the zeroes = c/a
Alpha × 1/alpha = ( k - 4 ) / 4
1 = ( k - 4 ) / 4
4 = k - 4
4 + 4 = k
8 = k
Therefore ,
k = 8
Answered by
2
Answer:
Compare 4x² - 2x + ( k - 4 ) with
ax² + bx + c ,
a = 4 ,
b = - 2 ,
c = k - 4 ,
Product of the zeroes = c/a
Alpha × 1/alpha = ( k - 4 ) / 4
1 = ( k - 4 ) / 4
4 = k - 4
4 + 4 = k
8 = k
Therefore ,
k = 8
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