Question

if alpha, beeta and gamma are the zeroes of the polynomial x^3-6x^2-x+30, then find the cubic polynomial​

Answer 1

Step-by-step explanation:Answer:αβ+β*gamma+gamma*α=-1

Step-by-step explanation:a=1,b=-6,c=-1,d=30

:αβ+β*gamma+gamma*α=c/a

=-1/1

=-1

therefore,alpha*beta+beta*gamma+gamma*alpha=-1

hope it helps you