Question

If alpha, beeta are the zeroes of polynomial (x²-2x-8), then form a quadratic polynomial whose zeroes are 3 alpha and 2 beeta.

Answer 1

Answer:

cdxgfhhswfsgjeodbffjjghjjhddyuiillpllkjfdxcfssdrfgd

Step-by-step explanation:

dgvrxtghdd

Answer 2

Answer:

Given α and β be the zeroes of polynomials, so the quadratic polynomial is :

x² - (α+β)x+αβ

Comparing above equation to the given equation,We have,

x ² −2x−8, so we have,

α+β=2 and αβ=−8

So, 3α+3β=3(α+β)=3×2=6 and

3α×3β=9αβ=9×(−8)=−72

Thus, the required quadratic polynomial is x²−3(α+β)x+9αβ

Putting the values of α+β and αβ in above equation, x² −6x−72.