Question

If alpha ,beta are the roots of x^-p(x+1)+c=0then(1+alpha)(1+beta)​

Answer 1

Answer:

1+c

Step-by-step explanation:

x^2-p(X+1)+c=0

x^2-px-p+c=0

sum of roots=alpha+beta=-b/a=(p)

product of roots =c/a=(c-p)

(1+alpha)(1+beta)=1+(alpha×beta)+(alpha+beta)

=1+c-p+p

=1+c