if alpha beta are the zeroes of polynomial p(x)=5x^2+5x+1 the find the value of 1) a^2+b^2 (2) a ^-1+ b^-1
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Hi mate !
A/Q
a and b are zeroes of p(x)
so
a+b= -5/5= -1
a×b= 1/5
1) a^2 + b^2= (a+b)^2 - 2ab
now put the values in the equation
a^2+b^2= (-1)^2-2×1/5=2-2/5=8/5
(2)1/a +1/b= (a+b)/ab
put values in the equation
-1×5/5=-5
A/Q
a and b are zeroes of p(x)
so
a+b= -5/5= -1
a×b= 1/5
1) a^2 + b^2= (a+b)^2 - 2ab
now put the values in the equation
a^2+b^2= (-1)^2-2×1/5=2-2/5=8/5
(2)1/a +1/b= (a+b)/ab
put values in the equation
-1×5/5=-5
siddhantcreatepahi81:
something goes wrong in the last line . actually it was divided by 1 .sorry
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