Question

If alpha ,beta, are the zeroes of the polynomial 2x3 + x2 -13x + 16 then find the value of alpha beta gama

Answer 1

Answer:

-8

Step-by-step explanation:

we have, 2x³+x²-13x+16

let alpha, beta and gama a, b and c respectively

the gernal equation of cubic polynomial is,

x³-(a+b+c)x²+(ab+bc+ca)x-(abc)

so, first of all we have to make the coefficient of x³ is one in above eq.

so, by dividing 2 above eq.

it will become as, x³+ x²/2-13/2x+8 by making it as gernal equation,

x³-(-1/2)x²+(-13/2)x-(-8)

comparing it by gernal equation,

the value of (abc) is -8

or the value of (alpha beta gama) is,-8 .....ans