If alpha beta are the zeros of polynomial x square + 7 x + 12 then find the value of one upon alpha plus one
AshuAbhishek1:
the required answer is 2/3
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x^2+7x+12 = 0
factorise this equation:
x^2 + 4x + 3x + 12 = 0
x(x+4) + 3 (x+4) = 0
therefore, (x+3) (x+4) = 0
= x = -3 OR -4
let -3 be alpha
and -4 be beta
1/ alpha + 1 = 1+(-3)/-3
= -2/-3
= 2/3
Hope this will help u:
factorise this equation:
x^2 + 4x + 3x + 12 = 0
x(x+4) + 3 (x+4) = 0
therefore, (x+3) (x+4) = 0
= x = -3 OR -4
let -3 be alpha
and -4 be beta
1/ alpha + 1 = 1+(-3)/-3
= -2/-3
= 2/3
Hope this will help u:
no
how can u say this ??
1+(-3)/-3 = -2/-3 = 2/3
hey sorry by mistake I had written
so sorry
The last calculation
Now I think this would help you *-*
by mistake I had written
sorry
Its ok
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