If alpha,beta are zeroes of the polynomial 3x^2+5x+2, find value of 1/alpha+1/beta
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Answered by
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let alpha and beta be m and n
m + n = 5/3
mn = 2/3
alpha^3 + beta^3
= m^3 + n^3
= (m+n)^3 - 3mn ( m+n )
= (5/3)^3 - 3×(2/3) (5/3)
= ( 125/27) - (10/3)
= ( 125 - 90 ) /27
= 35 / 27
m + n = 5/3
mn = 2/3
alpha^3 + beta^3
= m^3 + n^3
= (m+n)^3 - 3mn ( m+n )
= (5/3)^3 - 3×(2/3) (5/3)
= ( 125/27) - (10/3)
= ( 125 - 90 ) /27
= 35 / 27
Answered by
1
Here is your answer :-
Your equation is 3x²+5x+2
Let's factories it
3x²+5x+2
3x² +(3+2)x+2
3x² + 3x +2x +2
3x (x+1) +2 (x+1)
(x+1) (3x+2)
x = -1 , -2/3
sum of zeroes is -1 -2/3 = -5/3
product of zeroes is 2/3
so , value of 1/ alpha + 1/ beta
alpha + beta / alpha × beta
-5/3/2/3
-5/2
so your answer is -5/2
Hope it helps .....mark as brainiliest
Your equation is 3x²+5x+2
Let's factories it
3x²+5x+2
3x² +(3+2)x+2
3x² + 3x +2x +2
3x (x+1) +2 (x+1)
(x+1) (3x+2)
x = -1 , -2/3
sum of zeroes is -1 -2/3 = -5/3
product of zeroes is 2/3
so , value of 1/ alpha + 1/ beta
alpha + beta / alpha × beta
-5/3/2/3
-5/2
so your answer is -5/2
Hope it helps .....mark as brainiliest
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