Question

If alpha,beta are zeroes of the polynomial 3x^2+5x+2, find value of 1/alpha+1/beta

Plz answer

Answer 1

let alpha and beta be m and n
m + n = 5/3
mn = 2/3

alpha^3 + beta^3 
= m^3 + n^3
= (m+n)^3 - 3mn ( m+n )
= (5/3)^3 - 3×(2/3) (5/3)
= ( 125/27) - (10/3)
= ( 125 - 90 ) /27
= 35 / 27

Answer 2

Here is your answer :-

Your equation is 3x²+5x+2

Let's factories it

3x²+5x+2

3x² +(3+2)x+2

3x² + 3x +2x +2

3x (x+1) +2 (x+1)

(x+1) (3x+2)

x = -1 , -2/3

sum of zeroes is -1 -2/3 = -5/3

product of zeroes is 2/3

so , value of 1/ alpha + 1/ beta

alpha + beta / alpha × beta

-5/3/2/3

-5/2

so your answer is -5/2

Hope it helps .....mark as brainiliest