Question

If alpha, beta are zeroes of the x^2+7x+7, find the value of 1/alpha+ 1/beta - 2alphabeta.

Answer 1

Heya !!!

Here is your answer.

Given :
x² + 7x + 7
Here,
a = 1
b = 7, and
c = 7

Alpha + Beta = -b/a = -7
Alpha × Beta = c/a = 7

Now,
1/alpha + 1/beta - 2×alpha×beta
= (alpha+beta)/(alpha×beta) - 2 × alpha × beta
= -7/7 - 2× 7
= -1 - 14
= -15

Hope It Helps

Answer 2

Heya !!!


P(X) = X²+7X+7


Here,


A = 1 , B = 7 and C = 7



Sum of zeroes = -B/A


Alpha + Beta = -7/1


Alpha + Beta = -7


And,


Product of zeroes = C/A



Alpha × Beta= 7/1



Alpha × Beta = 7



1/ Alpha + 1/ Beta - 2 Alpha Beta



1/ Alpha + 1/ Beta - 2 × Alpha Beta





Beta + Alpha / Alpha Beta - 2 × Alpha Beta



-7 / 7 - 2 × 7



-7/7 - 14




=> -7 - 98/7




=> -105/7




=> -15




HOPE IT WILL HELP YOU....... :-)