Question

If alpha,beta are zeroes of xsquare-4x-3,find a quadratic polynomial whose zeroes are 3alpha and 3beta. Plzzz tell me fast

Answer 1

factorising above 
(x-1)(x-3)=0
alpha=1
beta=3
x^2-(3*3+1*3)x+(3*3*1*3)=0
x^2-12x+27=0

Answer 2

Alpha + beta =-b/a
That is,4/1= 4
Alpha × beta= c/a
That is, -3
ATQ, 3(alpha + beta)= sum
3alpha3beta
= 9alpha beta =product
X^2 - (sum)X+pdt
3×4=12 is sum
9×-3=-27 is pdt
Therefore quadratic polynomial =
X^2 - 12X -27