If alpha , beta are zeros of p( x) =ax2 +bx+ c then find alpha3 + beta3
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2
Answer:
2
Step-by-step explanation:
alpha+beta = -b/a
= -1/1
= -1
alpha×beta= c/a
= 1/1
= 1
alpha3+beta3
=(a+b)3
=(a+b)3-3ab(a+b)
= (-1)3-3×1(-1)
= -1-(-3)
= -1+3
= 2
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