if alpha,beta are zeros of the polynomial 4x^2+3x+7.find [1/alpha]+[1/beta]
Anonymous:
i think -3/7 is righteous answer
Answers
Answered by
4
Answer:
Alpha+beta= - b/a= - 4/3
Alpha * beta = c/a =7/4
1/alpha +1/beta = alpha +beta /alpha * beta = 4/3*4/7= - 16/21
Answered by
5
Heya!!
For a quadratic equations say
ax² + bx + c = 0
Alfa + Beta = -b/a
And
Alfa × Beta = c/a
_______________________________
here a = 4 , b = 3 And c = 7
Alfa + Beta = -3/4
And
Alfa × Beta = 7/4
=>
1/Alfa + 1/Beta =
{ Alfa + Beta }/ ( Alfa × Beta )
=>
1/Alfa + 1 / Beta = -16/21
For a quadratic equations say
ax² + bx + c = 0
Alfa + Beta = -b/a
And
Alfa × Beta = c/a
_______________________________
here a = 4 , b = 3 And c = 7
Alfa + Beta = -3/4
And
Alfa × Beta = 7/4
=>
1/Alfa + 1/Beta =
{ Alfa + Beta }/ ( Alfa × Beta )
=>
1/Alfa + 1 / Beta = -16/21
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