Question

If alpha+beta+gama=5,alpha beta+beta gama+gama alpha=7,alpha. Beta. Gama=9 then write the cubic polynomial having alpha, beta, gama ​

Answer 1

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Answer 2

Given:-

$\rule{200}{1}$

[♦Note:- ω=Gamma]

$\rule{200}{1}$

→α+β+ω=5

→αβ+βω+αω=7

→αβω=9

$\rule{200}{1}$

To find:-

The Cubic Polynomial?

$\rule{200}{1}$

Proof:-

•Using Cubic Polynomial formula•

→k[x³-(α+β+ω)x²+(αβ+βω+αω)x-(αβω)]

•Putting the Values•

→k[x³-(5)x²+(7)x-(9)]

★Let k=1★

→1[x³-5x²+7x-9]

→x³-5x²+7x+9

♦Hence, x³-5x²+7x+9 is the Cubic Polynomial having α,β,ω.

$\rule{200}{8}$