Question

if alpha beta gama are the roots of the equation x^3-6x^2+11x +6=0 then evaluate plz answer it

Answer 1

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Answer 2

Answer:

24

Step-by-step explanation:

given

alpha,beta,gama are the roots of the equation  

x^3-6x^2+11x-6=0

S1=alpha+beta+gama=6

S2=(alpha*beta)+(beta*gama)+(gama*alpha)=11

S3=alpha*beta*gama=6

then,alpha^2+beta^2+gama^2

=(alpha+beta+gama)^2-2[(alpha*beta)+(beta*gama)+(gama*alpha)]

=6^2-2(6)

=36-12

=24

               hope you all understant my answer