if alpha beta gama are zeroes of acubic polynomial x3 - 12x2+44x+c and 2alpha=beta +gama that find value of c
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Step-by-step explanation:
we know α+β+Φ=-b/a------------------(1)
so from equation 12/1
we know 2α=β+Φ
so α=β+Φ/2
subs the value of alpha in (1)
β/2+Φ/2+β+Φ=12
so β+Φ=8
we know 2α=β+Φ
here 2α=8
α=4
we know α.β.Φ=-d/a
4βΦ=c
so βΦ=c/4
β=c/4Φ
taking 2 at a time
αβ+ βΦ+Φα=44
4β+c+4Φ=44
4(β+Φ)=44-c----β+Φ=44-c/4(took β+Φ)
c+4Φ/4=8( 2α=β+Φ)
8=44-c/4(α=4)
32=44-c
so C=12
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