If alpha beta gamma all the zeros of the polynomial 6 x cube + 3 x square - 5 x + 1 then find the value of Alpha -1 + beta -1 plus 1 Gamma -1
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given polynomial is 6x³ + 3x² -5x +1
we have to find the value of α - 1 + β - 1 + gamma - 1
⇒ α+β+gamma-3
α+β+gamma = -b/a
= -3/6
= -1/2
therefore the value of α - 1 + β - 1 + gamma - 1
= -1/2-3
= -7/2
we have to find the value of α - 1 + β - 1 + gamma - 1
⇒ α+β+gamma-3
α+β+gamma = -b/a
= -3/6
= -1/2
therefore the value of α - 1 + β - 1 + gamma - 1
= -1/2-3
= -7/2
viniljain098:
Thanks bro
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