Question

if alpha beta gamma are the zeroes of 3xcube-19xsquare+33-9=0 find the value of 1. alpha+beta+gamma 2.alpha*beta+beta*gamma+alpha*gamma 3.alpha*beta*gamma

Answer 1

Answer:

sorry bro idont know the answere

Answer 2

Step-by-step explanation:

1) alpha + beta + gamma = -b/a

=> -b/a = 19/3

2) alpha*beta + beta*gamma + gamma*alpha =c/a

=> c/a = 33/3 = 11

3) alpha*beta*gamma = -d/a

=> -d/a = 9/3 = 3