Question

if alpha, beta, gamma are zeroes of the cubic polynomial at x3+2x2-9x+3, then find the value of alpha-1+beta-1+gamma-1​

Answer 1

Step-by-step explanation:

given

x^3+2x^2 -9x+3

(alpha-1)+(beta-1)+(gamma-1)

(alpha +beta+gama)-(1+1+1)

alpha +beta+gama-3

alpha +beta+gama= sum of roots = -b/a

=-2/1

-2

alpha +beta+gama-3

-2-3

= -5 is answer obtained