if alpha, beta, gamma are zeroes of x cube +px (square)+ qx + 2 such that alpha *beta +1 =0 then find value of 2p+q+5
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Px^ +qx +2 =0 compared by eqn. ax^ +bx+c =0-
a=p, b=q, c=2
α+β=-q/p ,αβ=2/p
α+β=αβ
-q/p=2/p
q= -2
and given that
αβ+1 =0
2/p+1=0
2+p=0
p=-2
hence
2p+q+5
=2(-2)+(-2)+5
=-4-2+5
=-6+5
=-1
a=p, b=q, c=2
α+β=-q/p ,αβ=2/p
α+β=αβ
-q/p=2/p
q= -2
and given that
αβ+1 =0
2/p+1=0
2+p=0
p=-2
hence
2p+q+5
=2(-2)+(-2)+5
=-4-2+5
=-6+5
=-1
himash:
wrong
ok
Ryt aap kriye
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