Question

if alpha + beta = pi/4, then the value of (1+tanalpha)(1+tanbeta)​

Answer 1

Answer:

tan(α+β)=tan4π

⟹1−tanαtanβtanα+tanβ=1

⟹tanα+tanβ+tanαtanβ=1

⟹1+tanα+tanβ+tanαtanβ=2

⟹(1+tanα)(1+tanβ)=2