Question

if m = cos theta - sin theta and n = cos theta + sin theta , then what is the value of sec^2 theta. answer is 4/(m=n)^2 ..

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Answer 1

Answer:

m=sinθ+cosθ⟹m

2

=sin

2

θ+cos

2

θ+2sinθcosθ=1+2sinθcosθ

⟹sinθcosθ=

2

m

2

−1

n=secθ+cosecθ=

sinθcosθ

sinθ+cosθ

=

2

m

2

−1

m

⟹n(m

2

−1)=2m⟹n(m+1)(m−1)=2m

Answer 2

Answer:

4/(m=n)^2

this is the correct answer OK