if alpha nd beta are zeroes of polynomial x²h3x+k such that alpha is equal to 2 beta fink k
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alpha+ beta=-b/a
given that: alpha=2beta....(1)
so,
2beta+beta=-(-3)
3beta=3
beta=3/3
beta=1(use this value in eq1)
we get,
alpha=2
now,
alpha*beta=c/a
2*1=k
k=2 is the answer
Anonymous:
hlo
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Given alpha and beta are zeroes of polynomial f(x) = x^2-3x+k . We know ax^2+ bx+ c =0 .
Then alpha + beta= -b/a and alpha× beta= c/a . In this case
alpha+ beta= 3
3beta= 3. ( Given alpha= 2beta)
Beta=1 .
and Alpha× beta= c/a.
2beta×1 = k
k= 2 beta ( and since beta= 1 then alpha+ beta= 1 ,alhpa =2 ) we get k = 2.I hope my answer help you.
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