Question

If α & β are zeroes of x^2 - 4x + 1 , then 1/α^3 + 1/ β^3 =

Answer 1

Answer:

Step-by-step explanation:

let alpha and beeta are taken as a and b

sum of zeros=4=a+b

a+b)^2=16

a^2+b^2+2ab=16

a^2+b^2=14

product of zeros=1=ab

1/a^3+1/b^3=a^3+b^3/a^3*b^3

(a+b)(a^2-ab+b^2)/a^3*b^3

=4*(a^2+b^2-1)/1

=4*(13)

=52