Question

three dice are thrown simultaneously probability of getting a number on the third die greater than the sum appeared in first two die​

Answer 1

Answer:

Three dice are thrown simultaneously.

There are 216 element in the total sample space.

Let us define an element A by assuming the numbers on the dice is 6

A=(2,2,2),(2,1,3),(2,3,1),(1,3,2),(1,2,3),(1,1,4),(4,1,1),(1,4,1),(3,1,2),(3,2,1)

B= getting a number 3 in all 3 dice =(2,2,2)

Since it is given that the event A has already occured.

i.e., the sum of the numbers on each die is 6

We have 10 cases out of which only one (2,2,2) is favourable to us.

∴P(B)=

10

1