Math, asked by nupurpandit6033, 6 months ago

If an=2n+3, find S20

Answers

Answered by sathyamargerate0410
1

Answer:

S20=480

Step-by-step explanation:

hope this answer helped you.

Attachments:
Answered by AlluringNightingale
1

Answer :

S(20) = 480

Note :

• Σc = c + c + c + . . . n times = nc , c is any constant .

• Σc·a(n) = c·Σa(n) , c is any constant .

• Σ[a(n) ± b(n)] = Σa(n) ± Σb(n)

• Sum of first n natural numbers is given as ; Σn = 1 + 2 + 3 + . . . + n = n(n+1)/2

• Sum of squares of n natural numbers is given as ;

Σn² = 1² + 2² + 3² + ... + n² = n(n+1)(2n+1)/6

• Sum of cubes of n natural numbers is given as ;

Σn³ = 1³ + 2³ + 3³ + . . . + n³ = [n(n+1)/2]²

• S(n) = Σa(n)

Solution :

  • Given : a(n) = 2n + 3
  • To find : S(20) = ?

We have ;

a(n) = 2n + 3

Also ,

We know that , S(n) = Σa(n)

Thus ,

=> S(n) = Σa(n)

=> S(n) = Σ(2n + 3)

=> S(n) = Σ2n + Σ3

=> S(n) = 2Σn + Σ3

=> S(n) = 2[n(n+1)/2] + 3n

=> S(n) = n(n + 1) + 3n

=> S(n) = n(n + 1 + 3)

=> S(n) = n(n + 4)

Now ,

=> S(20) = 20×(20 + 4)

=> S(20) = 20×24

=> S(20) = 480

Hence , S(20) = 480 .

Alternative method :

Note :

★ A linear polynomial in variable n always represents the nth term of an AP .

★ A quadratic polynomial in variable n always represents the sum of n terms of an AP .

★ A.P. (Arithmetic Progression) : A sequence in which the difference between the consecutive terms are equal is said to be in A.P.

★ If a1 , a2 , a3 , . . . , an are in AP , then

a2 - a1 = a3 - a2 = a4 - a3 = . . .

★ The common difference of an AP is given by ; d = a(n) - a(n-1) .

★ The sum of nth terms of an AP is given by ; S(n) = (n/2)×[ 2a + (n - 1)d ] .

or S(n) = (n/2)×(a + l) , l is the last term .

Solution :

  • Given : a(n) = 2n + 3
  • To find : S(20) = ?

We have ;

a(n) = 2n + 3

Thus ,

a(1) = 2×1 + 3 = 2 + 3 = 5

a(2) = 2×2 + 3 = 4 + 3 = 7

Now ,

The common difference will be ;

d = a(2) - a(1) = 7 - 5 = 2

Now ,

We know that , the sum of first n terms of an AP is given as ;

S(n) = (n/2)•[2a + (n -1)d]

Thus ,

The sum of first 20 terms will be ;

=> S(20) = (20/2)•[2a + (20 - 1)d]

=> S(20) = 10•(2a + 19d)

=> S(20) = 10•(2•5 + 19•2)

=> S(20) = 10•(10 + 38)

=> S(20) = 10•48

=> S(20) = 480

Hence , S(20) = 480 .

Similar questions