If an A.P . 17th term is 7 more than its 10tg term. Find the common difference.
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2
Answer:
let the 17th term be t17
therefore t17= a+ (17-1) d
a+16d
t10= a+ (10-1) d
a+9d
by given condition
t17=7+ t10
a+16d=7+ a+ 9d
a and -a get cancelled
so,
16d=7+9d
16d-9d=7
7d=7
therefore d=1
Answered by
1
Answer:
Hye... here is the answer.
Hope it helped you.
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