Question

if an acute angle triangle ABC Sin A + B minus C is equal to half cot a minus b + C is equal to zero and cos b + c minus is equal to half then find Angle A Angle B and angle C ​

Answer 1

Step-by-step explanation:

In an acute angled triangle ABC, if sin (A + B + C) = 1/2 and cos (B + C + A) = 1/√2, find ∠A, ∠B and ∠C. In an acute angled triangle ABC, if sin (A + B + C) = 1/2 and cos (B + C + A) = 1/√2, find ∠A, ∠B and ∠C.

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