Solve :-. (x-b-c)/a + (x-c-a)/b + (x-a-b)/c=3
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Solution :
Given,
(x - b - c)/a + (x - c - a)/b + (x - a - b)/c = 3
or, (x - b - c)/a + (x - c - a)/b + (x - a - b)/c = 1 + 1 + 1
or, {(x - b - c)/a - 1} + {(x - c - a)/b - 1} + {(x - a - b)/c - 1} = 0
or, (x - b - c - a)/a + (x - c - a - b)/b + (x - a - b - c)/c = 0
or, (x - a - b - c) (1/a + 1/b + 1/c) = 0
or, x - a - b - c = 0, since a, b, c ≠ 0
or, x = a + b + c
Therefore, the required solution is
x = a + b + c ( Ans. )
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