Math, asked by vandna9712, 1 year ago

Solve :-. (x-b-c)/a + (x-c-a)/b + (x-a-b)/c=3

Answers

Answered by Swarup1998
8

Solution :

Given,

(x - b - c)/a + (x - c - a)/b + (x - a - b)/c = 3

or, (x - b - c)/a + (x - c - a)/b + (x - a - b)/c = 1 + 1 + 1

or, {(x - b - c)/a - 1} + {(x - c - a)/b - 1} + {(x - a - b)/c - 1} = 0

or, (x - b - c - a)/a + (x - c - a - b)/b + (x - a - b - c)/c = 0

or, (x - a - b - c) (1/a + 1/b + 1/c) = 0

or, x - a - b - c = 0, since a, b, c ≠ 0

or, x = a + b + c

Therefore, the required solution is

x = a + b + c ( Ans. )

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