Question

If an angel visits an asteroid called B 612 which has a radius of 20 m and mass of
104 kg, what will be the acceleration due to gravity in B 612 ?.

Answer 1

$1.73 \times {10}^{ - 11}$

Answer 2

Answer:

1.7342 10⁻¹¹  m/s²

Explanation:

g = GM / R²

G - Universal Constant - 6.67 × 10⁻¹¹ Nm²/kg²

M - Mass of asteroid = 104 kg

R - Radius of Asteroid - 20 m

acceleration due to gravity in Astroid B 612

=  6.67 × 10⁻¹¹ * 104 / (20)²

= 1.7342 10⁻¹¹  m/s²