if an angle differ from its complementary by 10 degree find the angle
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Answered by
0
let the first angle be x
therefore another angle is 90-x
Atp
x-(90-x)=10
x-90+x=10
2x=100
x=50°
another angle =40°
therefore another angle is 90-x
Atp
x-(90-x)=10
x-90+x=10
2x=100
x=50°
another angle =40°
Answered by
0
let the no. be x
(90-x )- x =10
90-2x =10
2x=90-10
2x=80
x=40
thus the angles are 50 and 40 degrees
(90-x )- x =10
90-2x =10
2x=90-10
2x=80
x=40
thus the angles are 50 and 40 degrees
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