If an angle is 10deg.more than its complement, than find that angle.
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Answered by
2
Hey!
SUM OF TWO COMPLEMENTARY ANGLES US 180°
Let the first angle be x°
The second angle = (x+10)°
Btp,
x+x+10=90
=> 2x=80
=> x=40
Therefore the first angle is 40° and the second angle is 50°
HOPE THIS HELPS YOU...
SUM OF TWO COMPLEMENTARY ANGLES US 180°
Let the first angle be x°
The second angle = (x+10)°
Btp,
x+x+10=90
=> 2x=80
=> x=40
Therefore the first angle is 40° and the second angle is 50°
HOPE THIS HELPS YOU...
9613661545:
Very very Thnx
Answered by
2
Hi !
Let the first angle be x°
Then the second angle is (x+10)°
we know that sum of complementary angles is 90°
i.e.,
x + x + 10 = 90
2x = 80
x = 40
Hence , first angle is 40° .
The other angle is 40 + 10 , i.e , 50°
Let the first angle be x°
Then the second angle is (x+10)°
we know that sum of complementary angles is 90°
i.e.,
x + x + 10 = 90
2x = 80
x = 40
Hence , first angle is 40° .
The other angle is 40 + 10 , i.e , 50°
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